alibOr

RWalib C Array Library User Guide > Logical Operations > alibOr

alibOr

Applies the | operator element-wise to scalar or array arguments. For general array-based code, this routine is most commonly used as a logical-or between arrays of 0's and 1's, e.g., arrays produced by relational operations. The PV-WAVE API for this routine is the operator OR.

Prototypes

void alibOrb( wvlong m, wvlong n, UCHAR *p, UCHAR *q, UCHAR *r )

void alibOrs( wvlong m, wvlong n, short *p, short *q, short *r )

void alibOri( wvlong m, wvlong n, int *p, int *q, int *r )

void alibOrl( wvlong m, wvlong n, wvlong *p, wvlong *q, wvlong *r )

Parameters

m — (Input) The number of elements in the first array operand. A value of 0 indicates that the first operand is a scalar.

n — (Input) The number of elements in the second array operand. A value of 0 indicates that the second operand is a scalar. If both operands are arrays then n must equal m.

*p — (Input) The pointer to the first operand.

*q — (Input) The pointer to the second operand.

*r — (Input/Output) The destination array. On return, array r contains the bitwise-or of the two operands, element-wise. For operands containing only 0's and 1's (e.g., arrays produced by relational operations) the bitwise-or is functionally equivalent to the logical-or. alibOr can be done in-place, i.e., r can equal p or q.

Example

#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include "alib.h"

void main() {

   /* make up some input data for the examples */

      UCHAR b0[5]={0,1,2,3,4}, b1[5]={0,1,0,1,0}, b2[5]={0,1,0,0,1}, b3=2;

   /* make an output array */

   UCHAR *b;

   b = (UCHAR*)malloc(5*sizeof(UCHAR));

   printf( "\n\n show the 5-element input array b0" );

      alibPrintArrayb( 1, 1, 1, 5, b0, NULL );

   printf( "\n\n find the bitwise-or of array b0 and the scalar b3=2" );

      alibinit( NULL, NULL, NULL, NULL );

      alibOrb( 5, 0, b0, &b3, b );

      alibPrintArrayb( 1, 1, 1, 5, b, NULL );

   printf( "\n\n now reverse operands and do the same operation in-place" );

      alibOrb( 0, 5, &b3, b0, b0 );

      alibPrintArrayb( 1, 1, 1, 5, b0, NULL );

   printf( "\n\n show the 5-element input arrays b1 and b2" );

      alibPrintArrayb( 1, 1, 1, 5, b1, NULL );

      alibPrintArrayb( 1, 1, 1, 5, b2, NULL );

   printf( "\n\n since the two input arrays contain only 0's and 1's, \n" );

   printf( " their bitwise-or is the same as their logical-or" );

      alibOrb( 5, 5, b1, b2, b );

      alibPrintArrayb( 1, 1, 1, 5, b, NULL );

   printf( "\n\n now do the same operation in-place on b2" );

      alibOrb( 5, 5, b1, b2, b2 );

      alibPrintArrayb( 1, 1, 1, 5, b2, NULL );

Output:

show the 5-element input array b0

   0   1   2   3   4

 find the bitwise-or of array b0 and the scalar b3=2

   2   3   2   3   6

 now reverse operands and do the same operation in-place

   2   3   2   3   6

 show the 5-element input arrays b1 and b2

   0   1   0   1   0

   0   1   0   0   1

 since the two input arrays contain only 0's and 1's,

 their bitwise-or is the same as their logical-or

   0   1   0   1   1

 now do the same operation in-place on b2

   0   1   0   1   1

Version 2017.0