StrBuf::operator =( const StrBuf & )

Assign a StrBuf from another StrBuf.

Virtual?	No
Class	`StrBuf`
Arguments	`const StrBuf &buf`	(implied) reference of the `StrBuf` from which assignment occurs
Returns	`void`

Notes

Initialize both StrBufs before the assignment.

Any memory allocated for the assigned StrBuf's buffer is separate from the memory for the StrBuf's buffer from which assignment occurs.

Do not assign a StrBuf to itself.

Example

Copy

#include &lt;iostream&gt;

#include &lt;stdhdrs.h&gt;
#include &lt;strbuf.h&gt;

int main( int argc, char **argv )
{
    StrBuf sba;
    StrBuf sbb;

    sba.Set( "xyz" );

    sbb = sba;   // assign StrBuf to StrBuf

    cout &lt;&lt; "sba.Text() returns \"" &lt;&lt; sba.Text() &lt;&lt; "\"\n";
    cout &lt;&lt; "sbb.Text() returns \"" &lt;&lt; sbb.Text() &lt;&lt; "\"\n";
}

Executing the preceding code produces the following output:

sba.Text() returns "xyz"
sbb.Text() returns "xyz"